LeetCode Solution - Problem Fizz Buzz

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

• 1 <= n <= 104

Solution:

Java:

class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> list = new ArrayList<>();
        for (int i=1; i <= n; i++) {
            if (i % 3 == 0 && i % 5 == 0) {
                list.add("FizzBuzz");
            } else if (i % 3 == 0) {
                list.add("Fizz");
            } else if ( i % 5 == 0) {
                list.add("Buzz");
            } else {
                list.add(Integer.toString(i));
            }
        }
        return list;
    }
}

Python3:

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        ans = []
        for i in range(1,n+1):
            if i%3 == 0 and i%5 == 0:
                ans.append("FizzBuzz")
            elif i%3 == 0:
                ans.append("Fizz")
            elif i%5 == 0:
                ans.append("Buzz")
            else:
                ans.append(str(i))
        return ans