HackerRank Python Solution - Regex and Parsing - Re.start() & Re.end()

start() & end():

• These expressions return the indices of the start and end of the substring matched by the group.

>>> import re
>>> m = re.search(r'\d+','1234')
>>> m.end()
4
>>> m.start()
0

Task:

• You are given a string S.
• Your task is to find the indices of the start and end of string k in S.

Input Format:

• The first line contains the string S.
• The second line contains the string k.

Constraints:

• 0 < len(S) < 100
• 0 < len(k) < len(S)

Output Format:

• Print the tuple in this format: (start _index, end _index).
• If no match is found, print (-1, -1).

Sample Input:

aaadaa
aa

Sample Output:

(0, 1)  
(1, 2)
(4, 5)

Solution:

import re
s = input()
k = input()

pattern = re.compile(k)
match = pattern.search(s)

if not match:
    print('(-1, -1)')

while match:
    print('({0}, {1})'.format(match.start(), match.end() - 1))
    match = pattern.search(s, match.start() + 1)

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