HackerRank Python Solution - Built-Ins - Any or All

any():
  • This expression returns True if any element of the iterable is true. If the iterable is empty, it will return False.
Code:

>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False
all():
  • This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.
Code:

>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False
Task:
  • You are given a space-separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.
Input Format:
  • The first line contains an integer N. N is the total number of integers in the list.
  • The second line contains the space-separated list of N integers.
Constraints:
  • 0 < N < 100
Output Format:
  • Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.
Sample Input:

5
12 9 61 5 14 
Sample Output:

True
Explanation:
  • Condition 1: All the integers in the list are positive.
  • Condition 2: 5 is a palindromic integer. Hence, the output is True.
  • Can you solve this challenge in 3 lines of code or less? There is no penalty for solutions that are correct but have more than 3 lines.
Solution:

N = int(input())

numbers = input().split()

print(all(int(num) >= 0 for num in numbers) and any(num==num[::-1] for num in numbers))
Disclaimer: The problem statement is given by hackerrank.com but the solution is generated by the Geek4Tutorial admin. If there is any concern regarding this post or website, please contact us using the contact form. Thank you!

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