HackerRank Python Solution - Built-Ins - Any or All

any():

• This expression returns True if any element of the iterable is true. If the iterable is empty, it will return False.

Code:

>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False

all():

• This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.

Code:

>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False

Task:

• You are given a space-separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.

Input Format:

• The first line contains an integer N. N is the total number of integers in the list.
• The second line contains the space-separated list of N integers.

Constraints:

• 0 < N < 100

Output Format:

• Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

Sample Input:

5
12 9 61 5 14 

Sample Output:

True

Explanation:

• Condition 1: All the integers in the list are positive.
• Condition 2: 5 is a palindromic integer. Hence, the output is True.
• Can you solve this challenge in 3 lines of code or less? There is no penalty for solutions that are correct but have more than 3 lines.

Solution:

N = int(input())

numbers = input().split()

print(all(int(num) >= 0 for num in numbers) and any(num==num[::-1] for num in numbers))

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