HackerRank Python Solution - Itertools Topic - itertools.combinations_with_replacement()

itertools.combinations_with_replacement(iterable, r):

• This tool returns r length subsequences of elements from the input iterable allowing individual elements to be repeated more than once.

• Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order.

Sample Code:

>>> from itertools import combinations_with_replacement
>>> 
>>> print list(combinations_with_replacement('12345',2))
[('1', '1'), ('1', '2'), ('1', '3'), ('1', '4'), ('1', '5'), ('2', '2'), ('2', '3'), ('2', '4'), ('2', '5'), ('3', '3'), ('3', '4'), ('3', '5'), ('4', '4'), ('4', '5'), ('5', '5')]
>>> 
>>> A = [1,1,3,3,3]
>>> print list(combinations(A,2))
[(1, 1), (1, 3), (1, 3), (1, 3), (1, 3), (1, 3), (1, 3), (3, 3), (3, 3), (3, 3)]

Task: You are given a string S. Your task is to print all possible size k replacement combinations of the string in lexicographic sorted order.

Input Format: A single line containing the string S and integer value k separated by a space. 

Constraints:

• 0 < k <= len(s)

• The string contains only UPPERCASE characters.

Output Format: Print the combinations with their replacements of string S on separate lines.

Sample Input:

HACK 2

Sample Output:

AA
AC
AH
AK
CC
CH
CK
HH
HK
KK

Solution:

from itertools import combinations_with_replacement

word, num = input().split()

print(*["".join(i) for i in combinations_with_replacement(sorted(word),int(num))],sep="\n")

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